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Php Syntax Error Unexpected T_unset

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And thus the reason of existence of when. Cause: - You can get this error if it is missing a ';' character (to finish a line of code, or in the code of a loop instruction). Thus, here are the results of some benchmarks performed comparing unset() of numerous variables to setting them to null (with regards to memory usage and processing time):

10 variables:
Unset:
his comment is here

It's sole purpose is to "unset" this variable, ie. The utf8_encode() function will convert the string to proper utf8 and invalid characters would be fixed, making the xml parseable by simplexml or domdocument.
/**
* function rambo (first blood)
*
* Completely and utterly destroys everything, returning the kill count of victims
*
*

Php Unset

Update: If you want to reindex the values of the array (in case you have a numeric array), you have to do it in two steps (as unset does not return share|improve this answer edited Nov 9 '10 at 11:46 answered Nov 9 '10 at 11:41 Ruel 8,27232239 add a comment| up vote 0 down vote Unset doesn't return anything: void unset Solution: - Check the prepare() statement for truthiness and if it is good you can proceed on to binding and executing, otherwise, get the SQL error which you can use to Personal Open source Business Explore Sign up Sign in Pricing Blog Support Search GitHub This repository Watch 9 Star 7 Fork 43 atoum/atoum-documentation forked from geraldcroes/atoum-s-old-documentation Code Issues 23 Pull

Why do units (from physics) behave like numbers? share|improve this answer answered Jun 30 at 4:49 pulla 86 add a comment| Your Answer draft saved draft discarded Sign up or log in Sign up using Google Sign up Downloads Documentation Get Involved Help PHP 7.1.0 Release Candidate 4 Released Getting Started Introduction A simple tutorial Language Reference Basic syntax Types Variables Constants Expressions Operators Control Structures Functions Classes and This is because the "global" function creates a reference to a variable at the time it's executed, so a variable can be deleted out from under a "global $my_variable" declaration in

The code in question is this: if(isset($a_filter[$_GET['id']]['disabled'])) unset($a_filter[$_GET['id']]['disabled']);Its testing if the item exists Php Remove Element From Array By Value Cause: - There is a class of the same name declared more than once. more hot questions question feed lang-php about us tour help blog chat data legal privacy policy work here advertising info mobile contact us feedback Technology Life / Arts Culture / Recreation http://forums.devnetwork.net/viewtopic.php?f=1&t=77144 Such a function can only work for variables that exist in a common or global scope (compare 'unset($_GLOBALS[variable])').

I don't know how PHP handles garbage collection internally, but I guess

Re: Error: Parse error: syntax error, unexpected T_UNSET ... What hardware are you using for testing? News: Get your appliances, shirts and more!https://store.pfsense.org Home Help Search Login Register pfSense Forum» pfSense English Support» General Questions» Error: Parse error: syntax error, unexpected T_UNSET ... share|improve this answer edited Jan 30 '14 at 19:59 answered Jan 30 '14 at 6:50 user2864740 35.3k43880 add a comment| up vote 0 down vote You can't assign "unset".

Php Remove Element From Array By Value

on line ... http://php.net/manual/en/function.unset.php It says:

If a static variable is unset() inside of a function, unset() destroys the variable and all its references.

function foo()

If you truly care about the ~4 microseconds saved over <50 variables, more power to you. this content Cause: - A syntax error before a "for()" instruction. If the website and database are both UTF-8, it should be ok to save php files as UTF-8 without BOM. - Read the error message carefully. Cause: - This error can appear when it is called a function without passing all the rquired arguments.

Yes, my password is: Forgot your password? Join them; it only takes a minute: Sign up PHP: syntax error help expected ; up vote 0 down vote favorite Can someone help me figure out why I'm getting a Objects are passed by references. weblink That's why php says: Parse error: syntax error, unexpected 'unset' (T_UNSET), expecting ยป)' It's really mising a ) in the example.

Cause: - Posible to miss a closing ')' to a conditional instruction. 'val 1', 2=>78); if(isset($aray['xy'])) echo $aray['xy']; • Parse error: syntax

How can I copy and paste text lines across different files in a bash script?

Cause: - It's because zip_open() failed to open the file and returned an error code instead of a resource. array_values expect an array as parameter, but unset does not have any return value. docteurklein commented Jul 17, 2013 Yeah thanks @marmotz but the problem is the explanation below :) It can't state the syntax error anymore. Otherwise, use unset() to minimize script impact on your system.
Note: Tested on PHP 5.3.8 installed via RPM on Fedora 14 up down 13 anon at no spam dot no address

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in Firewall Rules « Reply #3 on: April 17, 2008, 10:11:41 pm » Thank you very much hoba and sullrich!Yes the computer I'm using is really cheap. All of this is fucked up.