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Php Die Mysql Error


Most often, the output message from MySQL doesn't let you see enough of the query in the error message to let you see where your query went bad- it a missing Get the best of About Tech in your inbox. However, I would rather recommend something like this: mysql_query($sql); if (mysql_error()) die('Error, insert query failed'); If You are interested in why it died, then: mysql_query($sql); if ($error = mysql_error()) die('Error, insert Recomended use is just for debugging/building a script, and for general user-specific queries which would at the worst, leak the users own information to themself.

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See also MySQL: choosing an API guide and related FAQ for more information. Show Full Article Related How to close your MySQL connection from PHP Do you know how to close a MySQL connection? Why do you want to set an array in die() anyway? Capture the last error with an IF statement.


Browse other questions tagged php mysql or ask your own question. How much interest did Sauron have in Erebor? "Surprising" examples of Markov chains Problem to left align within a split Why would breathing pure oxygen be a bad idea? Not the answer you're looking for?

Was Sigmund Freud "deathly afraid" of the number 62? ScallioXTX 2010-09-23 15:45:54 UTC #6 xtiansimon said: Will someone tell me if the above code snippet should work? SQL: $sql - Error: ".mysqli_error(), E_USER_ERROR); This method is better than die because you can use it for development AND production, it's the permanent solution. Mysql_error Mysqli All Rights Reserved.

Not the answer you're looking for? Php Mysqli Error asked 4 years ago viewed 72080 times active 1 month ago Linked -1 Mysql query not inserting into database? Reputation: 220 Posts: 1,606 Joined: 20-January 09 Re: mysql query or die() problem Posted 16 March 2009 - 10:54 AM Out of shear curiosity, have you checked to make sure that navigate here Just include this function in every script.

Display Formatted Code Simple Content Formatting with Regular Expressions Limiting login attempts 151 More PHP Tutorials... Mysqli_query Error I'm still using the 4.x series for various compatibility reasons, so when I set up MySQL 5.0.x on IIS 6.0 running PHP 4.4.4 I was surpised to get this error from There is a bug in either documentation about error_reporting() or in mysql_error() function cause manual for mysql_error(), says: "Errors coming back from the MySQL database backend no longer issue warnings." Which mysql_error()) When you encounter an error, this will return your custom message (A MySQL error has occurred.
) followed by a line number, and the actual error.

Php Mysqli Error

How to make Twisted geometry How do I "install" CentOS? http://www.w3schools.com/php/func_misc_die.asp Troubleshooting is the only way that I can see to solve this problem. Die(mysql_error()) Did you mean ? Php Mysql Error Handling Yes that sure makes sense and it's a good idea to that.

I am designing a new exoplanet. http://iipseconline.com/mysql-error/php-mysql-error-1054.html What game is this picture showing a character wearing a red bird costume from? This post has been edited by gregwhitworth: 16 March 2009 - 09:33 AM Was This Post Helpful? 0 Back to top MultiQuote Quote + Reply #3 JackOfAllTrades Saucy! Should I boost his character level to match the rest of the group? Mysql_query Error

mysql_error() ) to get specific details about the error. –Aziz Jun 7 '12 at 10:58 mysql_error ? –triclosan Jun 7 '12 at 10:58 I tried all your Just comment out the whole script, and at the top connect to the db, then the table and retrieve that one column and echo the result. It just makes sense to capture the error at the closest point to the generation. navigate here more stack exchange communities company blog Stack Exchange Inbox Reputation and Badges sign up log in tour help Tour Start here for a quick overview of the site Help Center Detailed

Why don't browser DNS caches mitigate DDOS attacks on DNS providers? Mysql_query Or Die but like i said it does it at them all mysql_error());

This will print out something like...

A fatal MySQL error occured.
Query: SELECT * FROM table
Error: (err_no) Bla bla bla, you

At least not in this block of code. @user3112869 putting or die() in the loop condition will always trigger the die() when the loop ends regardless of if an error happened Does the code terminate? So also changes the second mysql_select_db the selected DB of $conn to 'db2'.

If you change the connection parameters of the second connection to, a new connection is Mysql Show Last Error In fact, MySQL 5.1 with PHP 5.2:

Warning: mysql_connect() [function.mysql-connect]: Unknown MySQL server host 'locallllllhost' (11001)

That's a warning, which is not trapped by mysql_error()! up down -1 Anonymous

many thanks for the quick help as usual. is there another way of producing this type of error and it not completely stopping, just produce the error and ignore it? (can only really think of it happening in action If you can get through then you know somewhere in your code you are listing something wrong. his comment is here Was This Post Helpful? 0 Back to top MultiQuote Quote + Reply #6 farril D.I.C Head Reputation: 0 Posts: 110 Joined: 04-March 09 Re: mysql query or die() problem Posted

Copyright 1999-2016 by Refsnes Data. Related 2787How can I prevent SQL injection in PHP?334Convert from MySQL datetime to another format with PHP530What is the best collation to use for MySQL with PHP?679How do I get PHP Copyright 1999-2016 by Refsnes Data. i think its because it doesn't finish the while() loop its inside at just cuts out.

What about PHP error. Movie about a board-game that asks the players touchy questions Words that are both anagrams and synonyms of each other Story about crystal flowers that stop time? Here's my code, $from= "Findings"; $where=""; if($service!= null) { $from = $from . ", ServiceType_Lookup"; $where= "Findings.ServiceType_ID= ServiceType_Lookup.ServiceType_ID AND ServiceType_Name= ". $service; if($keyword!= null) $where= $where . " AND "; } Useful for debugging.
if (!$result) {
$message = 'Invalid query:
. mysql_error() .